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\chapter[Prove that if $x \nmid yz$, then $x \nmid y$ and $x \nmid z$.]{Suppose $x$, $y$, and $z \in \bbz$, and $x \neq 0$. Prove that if $x \nmid yz$, then $x \nmid y$ and $x \nmid z$.}

\begin{remark*}
Give a proof by contrapositive.
\end{remark*}

\section{First draft}
Due Monday, March 14 at 6:00 PM.

\begin{proof}

\end{proof}